document.write( "Question 97183: A boy can do a piece of work in 15 days & his father ca do it in 10 days. How long will it take them to do the work together? \n" ); document.write( "

Algebra.Com's Answer #70998 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A boy can do a piece of work in 15 days & his father ca do it in 10 days. How long will it take them to do the work together?
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\n" ); document.write( "Let x = time required to complete the job together
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( " $\"x%2F15\"$ + $\"x%2F10\"$ = 1
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\n" ); document.write( "multiply equation by 30, to get rid of the denominator
\n" ); document.write( "30* $\"x%2F15\"$ + 30* $\"x%2F10\"$ = 30(1)
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\n" ); document.write( "Cancel out the denominators and you have:
\n" ); document.write( "2x + 3x = 30
\n" ); document.write( "5x = 30
\n" ); document.write( "x = 30/5
\n" ); document.write( "x = 6 hrs working together
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\n" ); document.write( "Check solution. Substitute 6 for x:
\n" ); document.write( " $\"6%2F15\"$ + $\"6%2F10\"$ = 1
\n" ); document.write( " $\"2%2F5\"$ + $\"3%2F5\"$ = 1 \n" ); document.write( "

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