document.write( "Question 1095311: A mother is presently four times as old as her daughter. The sum of their ages six years ago was 48. Find each persons current age.
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Algebra.Com's Answer #709861 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A mother is presently four times as old as her daughter. The sum of their ages six years ago was 48. Find each persons [sic] current age. \n" ); document.write( "--------- \n" ); document.write( "\"presently\" and \"current\" are superfluous. \n" ); document.write( "----------- \n" ); document.write( "A mother is four times as old as her daughter. The sum of their ages six years ago was 48. Find each person's age. \n" ); document.write( "---- \n" ); document.write( "The sum of their ages six years ago was 48 --> the sum is now 60. \n" ); document.write( "--- \n" ); document.write( "M = 4D \n" ); document.write( "M + D = 60 \n" ); document.write( "--- \n" ); document.write( "Sub for M \n" ); document.write( "4D + D = 60 \n" ); document.write( "D = 12 \n" ); document.write( "M = 48\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |