document.write( "Question 1095311: A mother is presently four times as old as her daughter. The sum of their ages six years ago was 48. Find each persons current age.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #709861 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A mother is presently four times as old as her daughter. The sum of their ages six years ago was 48. Find each persons [sic] current age.
\n" ); document.write( "---------
\n" ); document.write( "\"presently\" and \"current\" are superfluous.
\n" ); document.write( "-----------
\n" ); document.write( "A mother is four times as old as her daughter. The sum of their ages six years ago was 48. Find each person's age.
\n" ); document.write( "----
\n" ); document.write( "The sum of their ages six years ago was 48 --> the sum is now 60.
\n" ); document.write( "---
\n" ); document.write( "M = 4D
\n" ); document.write( "M + D = 60
\n" ); document.write( "---
\n" ); document.write( "Sub for M
\n" ); document.write( "4D + D = 60
\n" ); document.write( "D = 12
\n" ); document.write( "M = 48\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );