document.write( "Question 1095303: Jen Butler has been pricing Speed-Pass train fares for a group to New York. Three adults and four children must pay $80. Two adults and three children must pay $57. Find the price of the adult’s ticket and the price of the child’s ticket. \n" ); document.write( "

Algebra.Com's Answer #709841 by ikleyn(52909) $\"\"$ $\"About$

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document.write( "3a + 4c = 80,   (1)\r\n" );
document.write( "2a + 3c = 57.   (2)\r\n" );
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document.write( "Let us solve it using the Elimination method.\r\n" );
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document.write( "Multiply eq(1) by 2 (both sides. Multiply eq(2) by 3. You will get\r\n" );
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document.write( "6a + 8c = 160,   (3)\r\n" );
document.write( "6a + 9c = 171.   (4)\r\n" );
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document.write( "Now subtract eq(3) from eq(4). You will get\r\n" );
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document.write( "c = 171 - 160 = 11.\r\n" );
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document.write( "Thus the children ticket costs $11.\r\n" );
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document.write( "Then from eq(2), the adult tickets costs   = $12.\r\n" );
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document.write( "Please check it on your own.\r\n" );
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