document.write( "Question 97584:
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Algebra.Com's Answer #70983 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1st: 2x +(2/3)y =-8 \n" ); document.write( "2nd: (1/2)x -(1/3)y = 1 \n" ); document.write( "----------- \n" ); document.write( "Multiply thru 2nd by 2: \n" ); document.write( "1st: 2x + (2/3)y = -8 \n" ); document.write( "3rd: x - (2/3)y = 2 \n" ); document.write( "---------------- \n" ); document.write( "Add 1st and 3rd to solve for \"x\": \n" ); document.write( "3x = -6 \n" ); document.write( "x = -2 \n" ); document.write( "------------ \n" ); document.write( "Substitute into 1st (or 2nd) to solve for y: \n" ); document.write( "2*-2 + (2/3)y = -8 \n" ); document.write( "-4 + (2/3)y = -8 \n" ); document.write( "(2/3)y = -4 \n" ); document.write( "y = -6 \n" ); document.write( "============= \n" ); document.write( "Check the answer in 2nd. \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |