document.write( "Question 1095262: you are standing at c. 8 feet from a silo. A is the center of the circular base of the silo. the distance to point of tangency is 16 feet What is the radius of the silo \n" ); document.write( "
Algebra.Com's Answer #709825 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! Draw a 2-dimensional picture of the situation. \n" ); document.write( "From where you are standing at C, it is 16 feet to the point D on the \"edge\" of the silo (circle) as you see it. \n" ); document.write( "When it says you are 8 feet from the silo, it means that 8 feet is the shortest distance from C to any point on the silo (circle). Let B be that point on the circle that you are closest to. The line from where you are to that point B on the circle, extended through the circle to the other side of the circle at A, will pass through the center of the circle. That means AB is a diameter of the circle, which is of course twice the radius. \n" ); document.write( "So you will know the radius of the circle if you can use the given information to find the length of AB. \n" ); document.write( "And you do have enough information to do that. \n" ); document.write( "There is a theorem from geometry that says \n" ); document.write( " \n" ); document.write( "So if the radius is x (so that the diameter is 2x), \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The radius of the circle is 12 feet. \n" ); document.write( " |