document.write( "Question 1095257: A farmer has 84 feet of fence with which to make a corral. If he arranges it into a rectangle that is twice as long as it is wide, what are the dimensions?\r
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Algebra.Com's Answer #709815 by ikleyn(52803)\"\" \"About 
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document.write( "Let W be the width (in feet).\r\n" );
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document.write( "Then L = 2W feet, as the condition says.\r\n" );
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document.write( "Perimeter = L + W + L + W = 2W + W + 2W + W = 6W = 84  feet =======>  W = \"84%2F6\" = 14 feet.\r\n" );
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document.write( "L = 2*14 = 28 feet.\r\n" );
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document.write( "Answer.  L = 28 feet,  W = 14 feet.\r\n" );
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