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document.write( "Hi! I really find this problem difficult. Hoping someone could help me. Thanks!
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document.write( "(X)/(x-3) is greater than (2x-11)/(2x)
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document.write( "rational inequality
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document.write( "Based on the DENOMINATORS,
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document.write( "Therefore, we already have 2 critical values: 3 and 0\r\n" );
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------- Multiplying each side by LCD, (x - 3)(2x)\r\n" );
document.write( "
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document.write( "
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document.write( "17x > 33 \r\n" );
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document.write( "We now have 3 CRITICAL VALUES:
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document.write( "There now exists the following 4 (FOUR) INTERVALS that need to be tested. \r\n" );
document.write( "==========Interval 1: x < 0, or x = - 1\r\n" );
document.write( "
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document.write( "
------- Substituting - 1 for x\r\n" );
document.write( "
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document.write( "Is
? No!! Therefore, a solution DOES NOT exist in this interval.\r\n" );
document.write( "================
Interval 2:
, or x = 1\r\n" );
document.write( "
\r\n" );
document.write( "
------- Substituting 1 for x\r\n" );
document.write( "
\r\n" );
document.write( "Is
? Yes!! Therefore, a solution DOES exist in this interval.\r\n" );
document.write( "===============
Interval 3:
, or x = 2\r\n" );
document.write( "
\r\n" );
document.write( "
------- Substituting 2 for x\r\n" );
document.write( "
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document.write( "Is
? No!! Therefore, a solution DOES NOT exist in this interval.\r\n" );
document.write( "============
Interval 4: x > 3, or x = 4\r\n" );
document.write( "
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document.write( "
------- Substituting 4 for x\r\n" );
document.write( "
\r\n" );
document.write( "Is
? Yes!! Therefore, a solution DOES exist in this interval.
The solution, in INTERVAL NOTATION is:
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