document.write( "Question 1095225: find three consecutive odd integers such that 19 more than the first is 67 less than three times the last. \n" ); document.write( "

Algebra.Com's Answer #709776 by josmiceli(19441) $\"\"$ $\"About$

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Let the consecutive odd integers be:
\n" ); document.write( " $\"+n+\"$ , $\"+n%2B2+\"$ , and $\"+n+%2B+4+\"$
\n" ); document.write( "----------------------------------
\n" ); document.write( " $\"+n+%2B+19+=+3%2A%28+n+%2B+4+%29+-+67+\"$
\n" ); document.write( " $\"+n+%2B+19+=+3n+%2B+12+-+67+\"$
\n" ); document.write( " $\"+2n+=+19+%2B+67+-+12+\"$
\n" ); document.write( " $\"+2n+=+74+\"$
\n" ); document.write( " $\"+n+=+37+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+n%2B2+=+39+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+n+%2B+4+=+41+\"$
\n" ); document.write( "------------------
\n" ); document.write( "The numbers are 37, 39, and 41
\n" ); document.write( "--------------------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+n+%2B+19+=+3%2A%28+n+%2B+4%29+-+67+\"$
\n" ); document.write( " $\"+37+%2B+19+=+3%2A41+-+67+\"$
\n" ); document.write( " $\"+56+=+123+-+67+\"$
\n" ); document.write( " $\"+56+=+56+\"$
\n" ); document.write( "OK \n" ); document.write( "

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