document.write( "Question 1095115: If x=5y=2z then find x:y:z
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Algebra.Com's Answer #709693 by Theo(13342)\"\" \"About 
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what i get is the following:\r
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\n" ); document.write( "\n" ); document.write( "start with x=5y=2z\r
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\n" ); document.write( "\n" ); document.write( "if we put everything in terms of z, then we get:\r
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\n" ); document.write( "\n" ); document.write( "x = 2z\r
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\n" ); document.write( "\n" ); document.write( "y = 2/5 * z\r
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\n" ); document.write( "\n" ); document.write( "x:y:z in terms of z is therefore equalto 2z:2/5z:z\r
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\n" ); document.write( "\n" ); document.write( "multiply everything by 5 and you get 10z:2z:5z\r
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\n" ); document.write( "\n" ); document.write( "divide everything by z and you get 10 : 2 : 5\r
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\n" ); document.write( "\n" ); document.write( "the ratio of x : y : z is equal to 10 : 2 : 5\r
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\n" ); document.write( "\n" ); document.write( "there are 10 x's for every 2 y's for every 5 z's.\r
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\n" ); document.write( "\n" ); document.write( "the ratio of x/y = 10/2 = 5/1\r
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\n" ); document.write( "\n" ); document.write( "solve for x and you get x = 5y.\r
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\n" ); document.write( "\n" ); document.write( "the ratio of y/z = 2/5\r
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\n" ); document.write( "\n" ); document.write( "cross multiply to get 5y = 2z.\r
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\n" ); document.write( "\n" ); document.write( "the ratio of x : y : z looks good at 10 : 2 : 5\r
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