document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1095109>Question 1095109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Special solution:  Find one value for a and one value for b so that there are no values of x that makes the equation true. <BR>\n" );
document.write( " -3(2x-1)=ax+b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #709677 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=709677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Left side is -6x +3.\r<BR>\n" );
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document.write( "Take a = -6 and b = 4, and you will get the answer.\r<BR>\n" );
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document.write( "Indeed, the equation \r<BR>\n" );
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document.write( "-6x + 3 = -6x + 4 \r<BR>\n" );
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document.write( "has no solutions.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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