document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1095106>Question 1095106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pharmacist wishes to mix a solution that is 7&#8203;% Minoxidil. She has  on hand 60 ml of a 3&#8203;% solution and wishes to add some 9&#8203;% solution to obtain the desired 7&#8203;% solution. How much 9&#8203;% solution should she&#8203; add? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #709651 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=709651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>I will assume you will get at least one response that show the traditional algebraic method for solving this kind of problem; I will just show you my quick shortcut method....<br><BR>\n" );
document.write( "The 7% that she wants is \"twice as close\" to the 9% that is being added as it is to the 3% she is starting with.  That is, 9-7 = 2; while 7-3=4; 7 is \"twice as close to 9 as it is to 3\".<br><BR>\n" );
document.write( "Since the percentage of the mixture is twice as close to 9% as it is to 3%, she needs twice as much of the 9% as she has of the 3%.  Since she has 60ml of the 3%, she needs 120ml of the 9%.<br><BR>\n" );
document.write( "Answer: 120 ml </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );