document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1095096>Question 1095096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Seven decreased by three times a number is forty </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #709640 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=709640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = the number\r<BR>\n" );
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document.write( "7 - 3x = 40   {seven decreased by three times a number is 40}<BR>\n" );
document.write( "-3x = 33 {subtracted 7 from each side}<BR>\n" );
document.write( "x = -11   {divided each side by -3}\r<BR>\n" );
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document.write( "the number is -11<BR>\n" );
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