document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1095026>Question 1095026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the sum of b,c, and two times a is three times the sum of a minus b and a minus c, then a= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #709570 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=709570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b+c+2a=3{(a-b)+(a-c)}=3(2a-b-c)=6a-3b-3c<BR>\n" );
document.write( "2a+b+c=6a-3b-3c<BR>\n" );
document.write( "4a=4b+4c<BR>\n" );
document.write( "a=b+c<BR>\n" );
document.write( "check<BR>\n" );
document.write( "b+c+2b+2c=3{(b+c-b)+(b+c-c)}=3(c+b)<BR>\n" );
document.write( "3b+3c=3c+3b<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );