document.write( "Question 1094890: 1-Historical data indicates that only 20% of cable customers are willing to switch companies. If a binomial process is assumed, then in a sample of 20 cable customers, what is the probability that no more than 3 customers would be willing to switch their cable?
\n" ); document.write( "Answer 0.85 0.15 0.20 0.411 0.589\r
\n" ); document.write( "\n" ); document.write( "I know the answer is .411 but have no idea how I got there.
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Algebra.Com's Answer #709510 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!

This is a straightforward application of the binomial formula. If the probability is .2 that each customer is willing to switch and .8 that they are not, then the probability that n of the 20 customers will be willing to switch is
\n" ); document.write( "\"C%2820%2Cn%29%2A%28.8%5En%29%2A%28.2%5E%2820-n%29%29\"
\n" ); document.write( "where \"C(20,n)\" is \"20 choose n\".

\n" ); document.write( "Since you want the probability that no more than 3 of the 20 customers will be willing to change plans, the calculations you need to perform are...

\n" ); document.write( "\"C%2820%2C0%29%2A%28.8%5E20%29%2A%28.2%5E0%29\" [0 willing to switch];
\n" ); document.write( "\"C%2820%2C1%29%2A%28.8%5E19%29%2A%28.2%5E1%29\" [1 willing to switch];
\n" ); document.write( "\"C%2820%2C2%29%2A%28.8%5E18%29%2A%28.2%5E2%29\" [2 willing to switch]; and
\n" ); document.write( "\"C%2820%2C3%29%2A%28.8%5E17%29%2A%28.2%5E3%29\" [3 willing to switch]

\n" ); document.write( "Then of course you need to add the probabilities for those 4 cases.

\n" ); document.write( "The calculations are tedious with pencil and paper, and even with a scientific calculator; a spread sheet works nicely.

\n" ); document.write( "And .411 is the right answer....
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