document.write( "Question 97502This question is from textbook
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document.write( ": Heres the question:
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document.write( "A farmer wants to buy 100 animals for $100.00 (must buy at least one of them)\r
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document.write( "Horses-$5.00
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document.write( "Cows-$3.00
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document.write( "Chicks-.50 \r
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document.write( "How many horses,cows and chicks does the farmer need to have 100 and 100.00? \n" );
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Algebra.Com's Answer #70951 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! This problem involves diophantine equations, where you have more unknowns than equations. \n" ); document.write( "The solutions, however, are limited by the fact that the unknowns must be integers, i.e. whole cows, whole horses, etc. \n" ); document.write( "We can set up two equations as follows: H = number of horses, C = number of cows, and ch = number of chicks.\r \n" ); document.write( "\n" ); document.write( "From the problem description, we can write: \n" ); document.write( "H+C+ch = 100 The total number of animals is 100. \n" ); document.write( "($5)H+($3)C+($0.50)ch = $100 The total amount the farmer spends. \n" ); document.write( "The two equations are:\r \n" ); document.write( "\n" ); document.write( "1) H+C+ch = 100 \n" ); document.write( "2) 5H+3C+0.5ch = 100 Multiply this equation by 2 and subtract equation 1) from the result.\r \n" ); document.write( "\n" ); document.write( "1) H+C+ch = 100 \n" ); document.write( "2a) 10H+6C+ch = 200 \n" ); document.write( "-------------------- \n" ); document.write( "3) 9H+5C = 100 Subtract 9H from both sides. \n" ); document.write( "3a) 5C = 100-9H Now divide both sides by 5. \n" ); document.write( "3b) C = 20-(9/5)H Now C can only be an integer if H is a multiple of 5. Let's try H = 5. \n" ); document.write( "3c) C = 20-(9/5)(5) \n" ); document.write( "C = 20 - 9 \n" ); document.write( "C = 11 This is one possibility. Now let's try H = 10 \n" ); document.write( "3d) C = 20 - (9/5)(10) \n" ); document.write( "C = 20 - 18 \n" ); document.write( "C = 2 This is another possibility. \n" ); document.write( "H cannot be greater than 10 otherwise you would end up with C being a non-integer or a negative number.\r \n" ); document.write( "\n" ); document.write( "So, if C = 11 when H = 5, then ch = 100-11-5 = 84 - the number of chicks. \n" ); document.write( "Let's check this solution. \r \n" ); document.write( "\n" ); document.write( "H+C+ch = 100 \n" ); document.write( "5+11+84 = 100 and... \n" ); document.write( "5($5) + 11($3) + 84($0.50) = $25 + $33 + $42 = $100 This is a valid solution!\r \n" ); document.write( "\n" ); document.write( "Now if C = 2 when H = 10, then ch = 100-2-10 = 88 - the number of chicks. \n" ); document.write( "Let's check this solution. \n" ); document.write( "H+C+ch = 100 \n" ); document.write( "10+2+88 = 100 and... \n" ); document.write( "10($5)+2($3)+88($0.50) = $50+$6+$44 = $100 This solution is also valid!\r \n" ); document.write( "\n" ); document.write( "The two solutions are:\r \n" ); document.write( "\n" ); document.write( "1) 5 horses, 11 cows, and 84 chicks.\r \n" ); document.write( "\n" ); document.write( "2) 10 horses, 2 cows, and 88 chicks. \n" ); document.write( " \n" ); document.write( " |