document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97540>Question 97540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this:The second of two numbers is 3 less than twice the first.Their sum is 36. Find the numbers. so far i have tried,this:<BR>\n" );
document.write( "let x represent the first number<BR>\n" );
document.write( "let 3-x(2) represent the second number<BR>\n" );
document.write( "x+3-x(2)=36<BR>\n" );
document.write( "2x+3(2)=36<BR>\n" );
document.write( "2x+6=36<BR>\n" );
document.write( "2x=36-6<BR>\n" );
document.write( "2x=30<BR>\n" );
document.write( "2x divided by 2=30 divided by 2<BR>\n" );
document.write( "x=15<BR>\n" );
document.write( "15-3(2)=12(2)=24 <BR>\n" );
document.write( "so for my 2 numbers i have 15 and 24<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70948 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> CLOSE BUT NO CIGAR:<BR>\n" );
document.write( "X+Y=36<BR>\n" );
document.write( "NOW DEFINE Y=(2X-3) & REPLACE Y BY (2X-3) & SOLVE FOR THE X VALUE<BR>\n" );
document.write( "X+(2X-3)=36 <BR>\n" );
document.write( "X+2X-3=36<BR>\n" );
document.write( "3X=36+3<BR>\n" );
document.write( "X=39/3<BR>\n" );
document.write( "X=13 ANSWER FOR THE SMALLER NUMBER<BR>\n" );
document.write( "2*13-3=26-3=23 FOR THE LARGER NUMBER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "13+23=36<BR>\n" );
document.write( "36=36 &:<BR>\n" );
document.write( "13+(2*13-3)=36<BR>\n" );
document.write( "13+26-3=36<BR>\n" );
document.write( "13+23=36<BR>\n" );
document.write( "36=36<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );