document.write( "Question 1094875: A four sided die is rolled. If the outcome is \"1\" or \"2\", you roll once more; otherwise you stop. What is the probability that the sum of rolls is >= 4? \n" ); document.write( "
Algebra.Com's Answer #709469 by AnlytcPhil(1810)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I'm thinking that's wrong and that you should make a probability \r\n" );
document.write( "tree diagram of all possible outcomes, with the probability of \r\n" );
document.write( "going along each branch (line) written on the branch:\r\n" );
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document.write( "The successful outcomes are boxed in red.\r\n" );
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document.write( "The probability of getting the highest highlighted 4 on the \r\n" );
document.write( "right is to go along the branch from START to 1 (roll 1 first),\r\n" );
document.write( "with probability 1/4, and then go along the branch from 1 to \r\n" );
document.write( "the 4 (roll 4 second), with another probability of 1/4.  So\r\n" );
document.write( "the probability of getting the 4 by rolling a 1 first and then\r\n" );
document.write( "a 4, is gotten by multiplying the 1/4 to go from START to 1, times\r\n" );
document.write( "the 1/4 to go from the 1 to the 4. It is similar for the other \r\n" );
document.write( "outcomes on the far right\r\n" );
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document.write( "So \r\n" );
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document.write( "the probability of the upper highlighted 4 is (1/4)(1/4) = 1/16.\r\n" );
document.write( "the probability of the upper highlighted 5 is (1/4)(1/4) = 1/16.\r\n" );
document.write( "the probability of the other highlighted 4 is (1/4)(1/4) = 1/16.\r\n" );
document.write( "the probability of the other highlighted 5 is (1/4)(1/4) = 1/16.\r\n" );
document.write( "the probability of the highlighted 6 is (1/4)(1/4) = 1/16.\r\n" );
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document.write( "plus\r\n" );
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document.write( "the probability of the highlighted 4 on the bottom, the case where\r\n" );
document.write( "a 4 was rolled first and then you stopped is 1/4, so the desired\r\n" );
document.write( "probability is the sum of all those probabilities:\r\n" );
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document.write( "1/16 + 1/16 + 1/16 + 1/6 + 1/16 + 1/4 = 9/16.\r\n" );
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document.write( "Edwin

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