document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1094808>Question 1094808</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the  sum of three number in geometric  series is 14 and their product is 64.find the number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #709409 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=709409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>The first response you got is exactly right: mental arithmetic!  Algebra is overkill....<br><BR>\n" );
document.write( "You are given that the product is 64 and the sum is 14.  If both product and sum are whole numbers, then it is almost certain that the numbers are whole numbers.<br><BR>\n" );
document.write( "The product, 64 is 2^6; so all three of the numbers have to be powers of 2.<br><BR>\n" );
document.write( "And a little thought shows that the three numbers 2^1=2, 2^2=4, and 2^3=8 satisfy all the conditions of the problem. </SPAN>\n" );
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