document.write( "Question 1094819: An open box (with no lid) has a square base and four sides of equal height. The height is 2 greater than the length and width. What are the dimensions of the box if the volume is 96 cubic inches and the surface area is 112 square inches?\r
\n" ); document.write( "\n" ); document.write( "What is the width (and length) of the box?\r
\n" ); document.write( "\n" ); document.write( "What is the height of the box?
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Algebra.Com's Answer #709404 by josgarithmetic(39620) $\"\"$ $\"About$

You can put this solution on YOUR website!
Bottom dimensions x and x.
\n" ); document.write( "height y.\r
\n" ); document.write( "\n" ); document.write( " $\"y=x%2B2\"$ , ;
\n" ); document.write( " $\"y%2Ax%5E2=96\"$
\n" ); document.write( "and just those should be enough without using the surface area description $\"x%5E2%2B4xy=112\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%2B2%29%2Ax%5E2=96\"$
\n" ); document.write( " $\"x%5E3%2B2x%5E2-96=0\"$
\n" ); document.write( "One of the solutions is x=4.\r
\n" ); document.write( "\n" ); document.write( "This would make $\"highlight%28system%28x=4%2Cy=6%29%29\"$ \r
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\n" ); document.write( "check
\n" ); document.write( "6*4*4=96?
\n" ); document.write( "24*4=96
\n" ); document.write( "96
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\n" ); document.write( "4^2+4*4*6=112?
\n" ); document.write( "16+4*24=112
\n" ); document.write( "16+96
\n" ); document.write( "112
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\n" ); document.write( "Both conditions work.
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