document.write( "Question 1094699: a rectangular block of iron has to be cast so that its length is three times its width and its volume is a maximun,.find the dimensions of the block if its total surface area is not to exceed 1800 square cm \n" ); document.write( "
Algebra.Com's Answer #709374 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! rectangular block of iron has to be cast so that its length is three times its width and its volume is a maximun,. \n" ); document.write( "find the dimensions of the block if its total surface area is not to exceed 1800 square cm \n" ); document.write( ": \n" ); document.write( "let L = the length of block \n" ); document.write( "let x = the width \n" ); document.write( "let h = the height \n" ); document.write( ": \n" ); document.write( "The surface area equation \n" ); document.write( "2Lx + 2Lh + 2xh = 1800 \n" ); document.write( "simplify divide by 2 \n" ); document.write( " xL + Lh + xh = 900 \n" ); document.write( "we know that L = 3x \n" ); document.write( "3x^2 + 3xh + xh = 900 \n" ); document.write( "3x^2 + 4xh = 900 \n" ); document.write( "4xh = 900 - 3x^2 \n" ); document.write( "h = \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( "The volume equation \n" ); document.write( "V = L * x * h \n" ); document.write( "Replace L with 3x \n" ); document.write( "V = 3x * x * h \n" ); document.write( "V = 3x^2*h \n" ); document.write( "Replace h with \n" ); document.write( "V = \n" ); document.write( "cancel x \n" ); document.write( "V = \n" ); document.write( "V = \n" ); document.write( "Plot this equation, volume vertical, width horizontal \n" ); document.write( " \n" ); document.write( "We can see max volume occurs when x=10 which is the width \n" ); document.write( ": \n" ); document.write( "Find the dimensions \n" ); document.write( "L = 3(10) \n" ); document.write( "L = 30 cm \n" ); document.write( "w = 10 cm \n" ); document.write( "h = \n" ); document.write( "h = \n" ); document.write( "h = 15 cm is the height \n" ); document.write( ": \n" ); document.write( "30 * 10 * 15 = 4500 cu/cm is max volume \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the surface area with these dimensions \n" ); document.write( "2(30*10) + 2(30*15) + 2(10*15) = \n" ); document.write( "600 + 900 + 300 = 1800 sq cm \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |