document.write( "Question 1094699: a rectangular block of iron has to be cast so that its length is three times its width and its volume is a maximun,.find the dimensions of the block if its total surface area is not to exceed 1800 square cm \n" ); document.write( "
Algebra.Com's Answer #709374 by ankor@dixie-net.com(22740)\"\" \"About 
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rectangular block of iron has to be cast so that its length is three times its width and its volume is a maximun,.
\n" ); document.write( "find the dimensions of the block if its total surface area is not to exceed 1800 square cm
\n" ); document.write( ":
\n" ); document.write( "let L = the length of block
\n" ); document.write( "let x = the width
\n" ); document.write( "let h = the height
\n" ); document.write( ":
\n" ); document.write( "The surface area equation
\n" ); document.write( "2Lx + 2Lh + 2xh = 1800
\n" ); document.write( "simplify divide by 2
\n" ); document.write( " xL + Lh + xh = 900
\n" ); document.write( "we know that L = 3x
\n" ); document.write( "3x^2 + 3xh + xh = 900
\n" ); document.write( "3x^2 + 4xh = 900
\n" ); document.write( "4xh = 900 - 3x^2
\n" ); document.write( "h = \"%28%28900-3x%5E2%29%29%2F%284x%29\" \r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( "The volume equation
\n" ); document.write( "V = L * x * h
\n" ); document.write( "Replace L with 3x
\n" ); document.write( "V = 3x * x * h
\n" ); document.write( "V = 3x^2*h
\n" ); document.write( "Replace h with \"%28%28900-3x%5E2%29%29%2F%284x%29\"
\n" ); document.write( "V = \"%283x%5E2%28900-3x%5E2%29%29%2F%284x%29\"
\n" ); document.write( "cancel x
\n" ); document.write( "V = \"%283x%28900-3x%5E2%29%29%2F%284%29\"
\n" ); document.write( "V = \"%28%282700x+-+9x%5E3%29%29%2F4\" or 675x - 2.25x^3
\n" ); document.write( "Plot this equation, volume vertical, width horizontal
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+20%2C+-1000%2C+5000%2C+675x-2.25x%5E3%29+\"
\n" ); document.write( "We can see max volume occurs when x=10 which is the width
\n" ); document.write( ":
\n" ); document.write( "Find the dimensions
\n" ); document.write( "L = 3(10)
\n" ); document.write( "L = 30 cm
\n" ); document.write( "w = 10 cm
\n" ); document.write( "h = \"%28%28900-3%2810%5E2%29%29%29%2F%284%2A10%29\"
\n" ); document.write( "h = \"%28900-300%29%2F40\"
\n" ); document.write( "h = 15 cm is the height
\n" ); document.write( ":
\n" ); document.write( "30 * 10 * 15 = 4500 cu/cm is max volume
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the surface area with these dimensions
\n" ); document.write( "2(30*10) + 2(30*15) + 2(10*15) =
\n" ); document.write( "600 + 900 + 300 = 1800 sq cm \r
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