document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1094746>Question 1094746</A>: <I><SPAN STYLE=\"word-break: break-all;\">  could you please help me express this as a single logarithm <BR>\n" );
document.write( "I don't know how to approach the 1/5 and the exponent 5\r<BR>\n" );
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document.write( "1/5 ln(x + 2)^5 + 1/2 [ln(x) &#8722; ln(x^2 + 3x + 2)^2] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #709371 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=709371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/5 ln(x + 2)^5 + 1/2 [ln(x) &#8722; ln(x^2 + 3x + 2)^2]<BR>\n" );
document.write( "The 1/5 just cancels the exponent 5.<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= ln(x + 2) + 1/2 [ln(x) &#8722; ln(x^2 + 3x + 2)^2] <BR>\n" );
document.write( "= ln(x + 2) + 1/2ln(x) &#8722; ln(x^2 + 3x + 2) <BR>\n" );
document.write( "= ln(x + 2) + 1/2ln(x) &#8722; ln[(x + 2)*(x + 1)]<BR>\n" );
document.write( "= ln(x + 2) + 1/2ln(x) &#8722; ln(x + 2) - ln(x + 1)<BR>\n" );
document.write( "= 1/2ln(x) - ln(x + 1)<BR>\n" );
document.write( "= ln(sqrt(x)) - ln(x + 1)<BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28sqrt%28x%29%2F%28x%2B1%29%29 ALIGN=MIDDLE  ALT=\"ln%28sqrt%28x%29%2F%28x%2B1%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );