document.write( "Question 1094790: At the city museum, child admission is
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document.write( "$5.80
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document.write( " and adult admission is
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document.write( "$9.90
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document.write( ". On Monday, four times as many adult tickets as child tickets were sold, for a total sales of
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document.write( "$1271.20
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document.write( ". How many child tickets were sold that day? \n" );
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Algebra.Com's Answer #709366 by Katarekt(3)![]() ![]() ![]() You can put this solution on YOUR website! Let c be # of child tickets sold \n" ); document.write( "Let a be # of adult tickets sold\r \n" ); document.write( "\n" ); document.write( "a=4c (eq. 1) \n" ); document.write( "1271.20=5.80c+9.90a (eq. 2) \n" ); document.write( "sub eq. 1 into eq. 2, since a=4c \n" ); document.write( "1271.20=5.80c+9.90(4c) \n" ); document.write( "1271.20=5.80c+39.60c \n" ); document.write( "1271.20=45.40c \n" ); document.write( "1271.20/45.40=c \n" ); document.write( "c=28\r \n" ); document.write( "\n" ); document.write( "Therefore, 28 child tickets were sold that day.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |