document.write( "Question 1094771: 5^(2x+1) + 25 = 5^(x+3) + 5^x \n" ); document.write( "

Algebra.Com's Answer #709352 by ikleyn(52803) $\"\"$ $\"About$

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document.write( "Your equation is\r\n" );
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document.write( " = ,   or, which is the same,\r\n" );
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document.write( " = 0.\r\n" );
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document.write( "Introduce new variable  u = .  Then your equation will take the form\r\n" );
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document.write( " = 0.\r\n" );
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document.write( "Apply the quadratic formula to find the solutions for u:\r\n" );
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document.write( " =  = .\r\n" );
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document.write( " =  = 25;\r\n" );
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document.write( " =  = .\r\n" );
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document.write( "From  = 25 =  you get the solution for x: x= 2.\r\n" );
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document.write( "From  =  =  you get another solution for x: x= -1.\r\n" );
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document.write( "Answer.  The original equation has two solutions:  x = 2  and  x = -1.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The method of introducing new variable I showed you in this solution, is the standard method for problems like this.\r
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\n" ); document.write( "\n" ); document.write( "To see more examples of problems solved in this way, see the lesson\r
\n" ); document.write( "\n" ); document.write( " - Solving exponential equations\r
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