document.write( "Question 1094753: The six term of an arithmetic progression is 23 and the sum of the first six terms is 78.Find
\n" ); document.write( "(a)the common difference and the first term
\n" ); document.write( "(b)the tenth term
\n" ); document.write( "

Algebra.Com's Answer #709340 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!

A key concept in working with arithmetic sequences and series is that you can always group the terms in pairs so that the sum in each pair is the same; or, if the number of terms in the sequence is odd, there will be a single term in the middle that is half of that common sum.

\n" ); document.write( "So here is how I would work this problem....

\n" ); document.write( "The sum of the first 6 terms is 78. That means there are 3 pairs of terms, with each pair having a sum of 78/3 = 26.

\n" ); document.write( "The 6th term is 23; it pairs up with the first term; and the sum of the first and 6th terms is 26. That means the first term is 26-23 = 3.

\n" ); document.write( "The 6th term, 23, is the first term, 3, plus the common difference 5 times:
\n" ); document.write( "\"23+=+3+%2B+5d\"
\n" ); document.write( "\"20+=+5d\"
\n" ); document.write( "\"d+=+4\"

\n" ); document.write( "We are done with part (a): the common difference is 4; the first term is 3.

\n" ); document.write( "Part (b) is now easy. The 10th term is the first term, plus the common difference 9 times:
\n" ); document.write( "\"3+%2B+9%284%29+=+3%2B36+=+39\"
\n" ); document.write( "
\n" );