document.write( "Question 97513: i have to find the center of a circle with an equation (x-2)squared+(y+3)squared=16 \n" ); document.write( "
Algebra.Com's Answer #70933 by mathslover(157)\"\" \"About 
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\n" ); document.write( " the general equation of a circle is \r
\n" ); document.write( "\n" ); document.write( " \"%28x-x1%29%5E2+%2B+%28y-y1%29%5E2+=+r%5E2+\" where (x1,y1) is the center of the circle and
\n" ); document.write( " r its radius\r
\n" ); document.write( "\n" ); document.write( "given
\n" ); document.write( " equation of the circle
\n" ); document.write( " \"+%28x-2%29%5E2+%2B+%28y+%2B+3%29%5E2+=+16+\"\r
\n" ); document.write( "\n" ); document.write( "rewriting this equation in the standard form
\n" ); document.write( " \"+%28x-2%29%5E2+%2B+%28y+-+%28-3%29%29%5E2+=+4%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "clearly the centre is (2,-3) and the radius 4
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