document.write( "Question 1094753: The six term of an arithmetic progression is 23 and the sum of the first six terms is 78.Find
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Algebra.Com's Answer #709325 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "The \"highlight%28cross%28six%29%29\" sixth term of an arithmetic progression is 23 and the sum of the first six terms is 78.Find
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document.write( "Since the sum of the six terms is 78 and the 6-th term is 23, the sum of the first 5 terms is 78-23 = 55.\r\n" );
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document.write( "In turn, it means that the 3-rd term, which is exactly in the middle of that five terms, is  \"55%2F5\" = 11.\r\n" );
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document.write( "Thus we know that \"a%5B3%5D\" = 11  and  \"a%5B6%5D\" = 23.  The difference  \"a%5B6%5D\" - \"a%5B3%5D\" =   23-11 = 12 is exactly 3 times the common difference.\r\n" );
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document.write( "Hence, the common difference is \"12%2F3\" = 4.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Now you know ALL about this progression and can answer any question on your own.\r
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\n" ); document.write( "On arithmetic progressions, see the introductory lessons \r
\n" ); document.write( "\n" ); document.write( "    - Arithmetic progressions\r
\n" ); document.write( "\n" ); document.write( "    - The proofs of the formulas for arithmetic progressions \r
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\n" ); document.write( "\n" ); document.write( "    - Word problems on arithmetic progressions\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-II in this site\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic \"Arithmetic progressions\".\r
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\n" ); document.write( "\n" ); document.write( "Save the link to this textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-II
\n" ); document.write( "https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson\r
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