document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1094536>Question 1094536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 12 years old Ryan is three times as old as his brother Jeffrey,how old Will Ryan be when he is twice as old as his brother Jeffrey  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #709144 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=709144\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ryan is 12; Jeffrey is 4. Let n be the time before Ryan is twice Jeffrey's age. Then:<BR>\n" );
document.write( "12+n=2(4+n)<BR>\n" );
document.write( "12+n=8+2n<BR>\n" );
document.write( "n=4<BR>\n" );
document.write( "In 4 years Ryan will be 16; and Jeffrey will be 8<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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