document.write( "Question 97448: How many ounces of pure gold must be added to five ounces of something that is 1% gold in order that the mixture is 6% gold? \r
\n" ); document.write( "\n" ); document.write( "I tried working it out but I am not sure if I did it right. \r
\n" ); document.write( "\n" ); document.write( "x + 5(.01)= .06(x+5)
\n" ); document.write( "x + .05 = .06x + .30
\n" ); document.write( "x + .05 - .05 - .06x = .06x - .06x + .30 - .05
\n" ); document.write( ".94x = .25\r
\n" ); document.write( "\n" ); document.write( ".94x/.94 = .25/.94
\n" ); document.write( "x= .27 ounces
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #70912 by edjones(8007) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x=oz of pure gold
\n" ); document.write( "amount of alloy=5*.01= .05
\n" ); document.write( "amount of pure gold=1.00*x= x
\n" ); document.write( "amount of pure gold + alloy= .06(5+x)=.3+.06x
\n" ); document.write( ".05+x=.3+.06x
\n" ); document.write( ".94x=.25
\n" ); document.write( "x=.266 oz of pure gold
\n" ); document.write( "Check:
\n" ); document.write( ".266+5=5.266 total oz
\n" ); document.write( ".05+.266=.316 oz of pure gold
\n" ); document.write( ".316/5.266=.06 or 6%
\n" ); document.write( "You were right.
\n" ); document.write( "It was more difficult than usual to chek this one.
\n" ); document.write( "Keep up the good work!
\n" ); document.write( "Ed\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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