document.write( "Question 1094495: Determine the value of (p+q+r); if p,q, and r are positive integers, p^q = 8, and r^(1/p) = 7\r
\n" ); document.write( "\n" ); document.write( "This is what I tried but my answer doesn't match the answer key. Please see below:\r
\n" ); document.write( "\n" ); document.write( "p^q = 8 => 2^3 = 8\r
\n" ); document.write( "\n" ); document.write( "p = 2 and q = 3\r
\n" ); document.write( "\n" ); document.write( "Replacing the equation r^(1/p) = 7 with p gives me this:\r
\n" ); document.write( "\n" ); document.write( "r^(1/2) = 7\r
\n" ); document.write( "\n" ); document.write( "To make this equation true I assumed that the value of r should be 7:
\n" ); document.write( "7^(1/2) = 7
\n" ); document.write( "7 = 7\r
\n" ); document.write( "\n" ); document.write( "So, p+q+r = 2+3+7 = 12 but my answer key contains different answer. Please help.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #709086 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "You have p = 2 and q = 3 correct.
\n" ); document.write( "p^q = 2^3 = 8 is true\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If r^(1/p) = 7, then r^(1/2) = 7 meaning that r = 49 (not r = 7)
\n" ); document.write( "You square both sides to get rid of the exponent of 1/2 as shown below\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "r^(1/2) = 7
\n" ); document.write( "[ r^(1/2) ] ^2 = 7^2
\n" ); document.write( "r^(1/2*2) = 49
\n" ); document.write( "r^(2/2) = 49
\n" ); document.write( "r^1 = 49
\n" ); document.write( "r = 49\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So in summary:
\n" ); document.write( "p = 2, q = 3, r = 49\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Making
\n" ); document.write( "p+q+r = 2+3+49 = 5+49 = 54 which is the answer.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-----------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Side Note: exponents of 1/2 indicate square root. So for example \"x%5E%281%2F2%29%5E%22%22+=+sqrt%28x%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );