document.write( "Question 1094481: Farmer Del has 40 more chickens than cows on his farm. He also has 10 fewer pigs than cows and 20 fewer sheep than chickens. He also has 4 horses. If Farmer Del has a total of 110 animals on his farm, how many of each kind does he have? \n" ); document.write( "

Algebra.Com's Answer #709060 by ikleyn(52794) $\"\"$ $\"About$

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document.write( "Let the number of cows be x.\r\n" );
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document.write( "Then the number of chickens is (x+40),\r\n" );
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document.write( "     the number of pigs is (x-10),\r\n" );
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document.write( "     the number of sheep is ((x+40) - 20) = (x+20),\r\n" );
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document.write( "The number of horses is 4.\r\n" );
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document.write( "Altogether\r\n" );
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document.write( "    cows + chicken + pigs + sheep + horses = 110  ====>\r\n" );
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document.write( "     x   +  (x+40) + (x-10) + (x+20) + 4 = 110  ====>\r\n" );
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document.write( "    4x + 40 - 10 +20 + 4 = 110  ====>\r\n" );
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document.write( "    4x + 54 = 110  ====>  4x = 110-54 = 56  ====>  x =  = 14.\r\n" );
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document.write( "So, farmer Del has 14 cows.\r\n" );
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document.write( "From this point, can you complete the solution on your own ?\r\n" );
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