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document.write( "Straight line perpendicular to 5x-y = 1 has an equation\r\n" );
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document.write( "5y + x = c, (1)\r\n" );
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document.write( "where c is some (arbitrary) constant.\r\n" );
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document.write( " Our original line has the slope 5; so, the perpendicular line has the slope 
and has, therefore,\r\n" );
document.write( " the equation y = 
+ c, which is the same as (1).\r\n" );
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document.write( "So, all you need to do is to determine the constant \"c\" in equation (1).\r\n" );
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document.write( "For it, notice that straight line (1) has x-intercept (c,0) and y-intercept (0,
).\r\n" );
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document.write( "It means, that your right-angled triangle has the legs of 
and |c| units long.\r\n" );
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document.write( "Then its area is 
= 
square units.\r\n" );
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document.write( "You need to have this area equal to 5 square units. It gives you an equation\r\n" );
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document.write( " = 5,\r\n" );
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document.write( "which implies 
= 50 and then c = 
.\r\n" );
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document.write( "It means that your final equation under the question is\r\n" );
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document.write( "5y + x = .\r\n" );
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document.write( "Solved.\r
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document.write( "![\"\"](\"/images/stars/stars-13.gif\")
