document.write( "Question 97437: 2/3 +3y=5y-2/15 \n" ); document.write( "
Algebra.Com's Answer #70902 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2%2F3%2B3y=5y-2%2F15\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"%2815%29%282%2F3%2B3y%29=%2815%29%285y-2%2F15%29\" Multiply both sides by the LCM of 15. This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"10%2B45y=75y-2\" Distribute and multiply 15 by each term on both sides\r
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\n" ); document.write( "\n" ); document.write( "\"45y=75y-2-10\"Subtract 10 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"45y-75y=-2-10\" Subtract 75y from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-30y=-2-10\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"-30y=-12\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-12%29%2F%28-30%29\" Divide both sides by -30 to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=2+%2F+5\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"y=2+%2F+5\" (which is \"y=0.4\" in decimal form)
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