document.write( "Question 1094428: An executive invests $24000 some at 6% and the rest at 5% annual interest. If he receives an annual return of $1320 how much is invested at each rate \n" ); document.write( "
Algebra.Com's Answer #708974 by addingup(3677)\"\" \"About 
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Let the amount invested at 6% be x.
\n" ); document.write( "Then, the amount at 5% will be 24000-x
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\n" ); document.write( "0.06x + 0.05(24000 - x) = 1320
\n" ); document.write( "0.06x + 1200 - 0.05x = 1320
\n" ); document.write( "0.01x = 120
\n" ); document.write( "x = 120/0.01 = 12000 this is the amount invested at 6%
\n" ); document.write( "The amount at 5%: 24000 - 12000 = 12000
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\n" ); document.write( "Check:
\n" ); document.write( "12000*0.06 = 720
\n" ); document.write( "12000*0.05 = 600
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\n" ); document.write( "Total . . . 1320 Correct
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