document.write( "Question 1094428: An executive invests $24000 some at 6% and the rest at 5% annual interest. If he receives an annual return of $1320 how much is invested at each rate \n" ); document.write( "
Algebra.Com's Answer #708974 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Let the amount invested at 6% be x. \n" ); document.write( "Then, the amount at 5% will be 24000-x \n" ); document.write( "------------------------------- \n" ); document.write( "0.06x + 0.05(24000 - x) = 1320 \n" ); document.write( "0.06x + 1200 - 0.05x = 1320 \n" ); document.write( "0.01x = 120 \n" ); document.write( "x = 120/0.01 = 12000 this is the amount invested at 6% \n" ); document.write( "The amount at 5%: 24000 - 12000 = 12000 \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "Check: \n" ); document.write( "12000*0.06 = 720 \n" ); document.write( "12000*0.05 = 600 \n" ); document.write( ". . . . . . _____ \n" ); document.write( "Total . . . 1320 Correct \n" ); document.write( " \n" ); document.write( " |