document.write( "Question 97422: sqrt(2x+3)-sqrt(x+1)=1 \n" ); document.write( "
Algebra.Com's Answer #70896 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! sqrt(2x+3)=sqrt(x+1)+1 \n" ); document.write( "Square both sides to get: \n" ); document.write( "2x+3 = (x+1)+2sqrt(x+1) +1 \n" ); document.write( "2x+3 = x+2 + 2sqrt(x+1) \n" ); document.write( "x+1 = 2sqrt(x+1) \n" ); document.write( "Square again to gt: \n" ); document.write( "x^2+2x+1 = 4(x+1) \n" ); document.write( "x^2-2x-3=0 \n" ); document.write( "(x-3)(x+1)=0 \n" ); document.write( "x=3 or x=-1 \n" ); document.write( "------------- \n" ); document.write( "Checking answers in sqrt(2x+3)=sqrt(x+1)+1 \n" ); document.write( "If x=3: sqrt(9) = sqrt(4)+1 \n" ); document.write( "3 = 2+1 \n" ); document.write( "------------- \n" ); document.write( "If x=-1: sqrt(1) = sqrt(0)+1 \n" ); document.write( "1=1 \n" ); document.write( "--------------- \n" ); document.write( "Both values of x are valid. \n" ); document.write( "================ \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |