document.write( "Question 1094377: Two factory plants are making TV panels. Yesterday, Plant A produced 15,000 panels. Ten percent of the panels from Plant A and 3% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 8%? \n" ); document.write( "
Algebra.Com's Answer #708955 by hgv (5)\"\" \"About 
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Let the panels produced by Plant B be x.\r
\n" ); document.write( "\n" ); document.write( "Total produce by Panel A - 15,000
\n" ); document.write( "10% Defective :- 10% of 15,000
\n" ); document.write( " i.e. 1500\r
\n" ); document.write( "\n" ); document.write( "3% Defective by Plant B :- 3% of x
\n" ); document.write( " i.e. 3x/100\r
\n" ); document.write( "\n" ); document.write( "As given:\r
\n" ); document.write( "\n" ); document.write( "1500 + 3x/100 = 8% of total production by Plant A & B\r
\n" ); document.write( "\n" ); document.write( "Thus;\r
\n" ); document.write( "\n" ); document.write( "1500 + 3x/100 = 8/100 (15,000 + x)\r
\n" ); document.write( "\n" ); document.write( "1,50,000 + 3x = 1,20,000 + 8x\r
\n" ); document.write( "\n" ); document.write( "30,000 = 5x\r
\n" ); document.write( "\n" ); document.write( "x = 6,000\r
\n" ); document.write( "\n" ); document.write( "Hence, Plant B produce 6000 panels.\r
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