document.write( "Question 97177: After 5 hours of painting, Jess asked the for assistance of Jon.Together, they finished the job in 4 more hours.If Jon had joined in an hour after Jess started working, the job would have been finished in 7 hours. How long would it have taken for Jess to paint the house alone? \n" ); document.write( "
Algebra.Com's Answer #70895 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
After 5 hours of painting, Jess asked the for assistance of Jon. Together, they finished the job in 4 more hours.If Jon had joined in an hour after Jess started working, the job would have been finished in 7 hours. How long would it have taken for Jess to paint the house alone?
\n" ); document.write( ":
\n" ); document.write( "Let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "Let x = time if Jess did the job alone
\n" ); document.write( ":
\n" ); document.write( "Let y = time if Jon did the job alone
\n" ); document.write( ":
\n" ); document.write( "We know that after 5 hrs, he would complete \"5%2Fx\" of the job
\n" ); document.write( ":
\n" ); document.write( "Jess alone for 5 hr, together with Jon for 4 hrs, (a total of 9 hrs)
\n" ); document.write( "\"5%2Fx\" + \"4%2Fx\" + \"4%2Fy\" = 1
\n" ); document.write( ":
\n" ); document.write( " 5y + 4y + 4x = xy
\n" ); document.write( ":
\n" ); document.write( " 9y + 4x = xy
\n" ); document.write( ":
\n" ); document.write( "Jess alone for 1 hr, together for 6 hr (a total of 7 hrs)
\n" ); document.write( "\"1%2Fx\" + \"6%2Fx\" + \"6%2Fy\" = 1
\n" ); document.write( ":
\n" ); document.write( "y + 6y + 6x = xy
\n" ); document.write( ":
\n" ); document.write( "7y + 6x = xy
\n" ); document.write( ":
\n" ); document.write( "Since both equations = xy, make them equal to each other
\n" ); document.write( "9y + 4x = 7y + 6x
\n" ); document.write( "9y - 7y = 6x - 4x
\n" ); document.write( "2y = 2x
\n" ); document.write( "y = x
\n" ); document.write( ":
\n" ); document.write( "Rewrite the initial work equation substituting x for y
\n" ); document.write( "\"5%2Fx\" + \"4%2Fx\" + \"4%2Fy\" = 1
\n" ); document.write( "\"5%2Fx\" + \"4%2Fx\" + \"4%2Fx\" = 1
\n" ); document.write( "\"13%2Fx\" = 1
\n" ); document.write( "Therefore x = 13 hrs for Jess to do it alone
\n" ); document.write( ":
\n" ); document.write( "The same time would be required by Jon (y), prove that in the 2nd work equation
\n" ); document.write( "Substitute 13 for x in the 2nd work equation, solve for y:
\n" ); document.write( "\"1%2Fx\" + \"6%2Fx\" + \"6%2Fy\" = 1
\n" ); document.write( "\"1%2F13\" + \"6%2F13\" + \"6%2Fy\" = 1
\n" ); document.write( "\"7%2F13\" + \"6%2Fy\" = 1
\n" ); document.write( "7y + 13(6) = 13y
\n" ); document.write( "78 = 13y - 7y
\n" ); document.write( "6y = 78
\n" ); document.write( "y = 13 hr, Jon alone also
\n" ); document.write( ":
\n" ); document.write( "Did this help? Make any sense to you?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );