document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97426>Question 97426</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321227573/algebrahomeworkh>College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The problem is -4x^2+8x=0.  So far I've done -4x^2+8x+7=0, 4x^2-8x-7=0 then I squared half of the coefficient of x and added to both sides and got 4x^2-8x+16=9 but I can't figure out how to get a perfect square.  Did I do something wrong in the first steps? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70893 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -4x^2+8x=0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "= -4x(x-2)=0<BR>\n" );
document.write( "-4x=0 or x-2=0<BR>\n" );
document.write( "x = 0 or x=2<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );