document.write( "Question 1094296: A 10-quart radiator contains a 40% antifreeze solution. How much of the solution needs to be drained out and replaced with pure antifreeze in order to raise the solution to 70% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #708874 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" =quarts of solution to be
\n" ); document.write( "drained and replaced with pure antifreeze
\n" ); document.write( "\"+.4x+\" = quarts of alcohol drained off
\n" ); document.write( "\"+.4%2A10+=+4+\" = quarts of alcohol originally
\n" ); document.write( "in the radiator
\n" ); document.write( "----------------------------------------
\n" ); document.write( "\"+4+-+.4x+%2B+x+%29+%2F+10+=+.7+\"
\n" ); document.write( "\"+%28+4+%2B+.6x+%29+%2F+10+=+.7+\"
\n" ); document.write( "\"+4+%2B+.6x+=+7+\"
\n" ); document.write( "\"+.6x+=+3+\"
\n" ); document.write( "\"+x+=+5+\"
\n" ); document.write( "-------------
\n" ); document.write( "5 quarts needs to be drained and replaced
\n" ); document.write( "with pure antifreeze
\n" ); document.write( "-----------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+4+%2B+.6%2A5+%29+%2F+10+=+.7+\"
\n" ); document.write( "\"+7%2F10+=+.7+\"
\n" ); document.write( "OK
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