document.write( "Question 1094270: Solve the following with substitution
\n" ); document.write( "\"+x%5E2-3x-sqrt%28x%5E2-3x%29=2+\"\r
\n" ); document.write( "\n" ); document.write( "My steps so far are \r
\n" ); document.write( "\n" ); document.write( "\"+U+=sqrt%28x%5E2-3x%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"+U%5E2+-+U+=+2+\"
\n" ); document.write( "\"+U%5E2-U-2=0+\"
\n" ); document.write( "\"+%28U-2%29%28U%2B1%29+\"
\n" ); document.write( " U= 2, -1 \r
\n" ); document.write( "\n" ); document.write( "Then I went back using 2, -1 to plug back in\r
\n" ); document.write( "\n" ); document.write( "\"+U+=sqrt%28x%5E2-3x%29+\"
\n" ); document.write( "And ended up getting \"+sqrt%28-2%29+\" and \"+sqrt%284%29+\" from both
\n" ); document.write( "But -2 cant be it, so that would leave me with the 4 or 2,-2?
\n" ); document.write( "I'm not sure how to go about this.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #708863 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!

You used substitution to find U = sqrt(x^2-3x) is equal to either -1 or 2.

\n" ); document.write( "\"sqrt%28x%5E2-3x%29+=+-1\" won't give you any solutions, because a square root is never negative.

\n" ); document.write( "\"sqrt%28x%5E2-3x%29+=+2\"
\n" ); document.write( "gives you solutions.
\n" ); document.write( "\"x%5E2-3x+=+4\"
\n" ); document.write( "\"x%5E2-3x-4+=+0\"
\n" ); document.write( "\"%28x-4%29%28x%2B1%29+=+0\"

\n" ); document.write( "The solutions are x=4 and x=-1; checking shows that both solutions work in the original equation.
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