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3(2x-3)-4(x-2) = -(x-5)\r
\n" ); document.write( "\n" ); document.write( "Start by distributing any variables into the expressions that have parentheses:
\n" ); document.write( "(tip: DO NOT FORGET TO DISTRIBUTE THE MINUS SIGN INTO THE EXPRESSION IF IT EXISTS)
\n" ); document.write( "=> 6x-9-4x+8 = -x+5\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:
\n" ); document.write( "=> 6x-4x-9+8 = -x+5
\n" ); document.write( "=> 2x-1 = -x+5\r
\n" ); document.write( "\n" ); document.write( "Isolate the variable x on the left side of the equation, and the numbers on the right side of the equation:
\n" ); document.write( "=> 2x-1+x=5
\n" ); document.write( "=> 3x-1 = 5
\n" ); document.write( "=> 3x = 5+1
\n" ); document.write( "=> 3x = 6
\n" ); document.write( "=> x = 6/3
\n" ); document.write( "=> x = 2\r
\n" ); document.write( "\n" ); document.write( "After finding the value of x, we can substitute its value back into the ORIGINAL EQUATION to check.
\n" ); document.write( "=> 3(2(2)-3)-4(2-2) = -(2-5)
\n" ); document.write( "=> 3(4-3)-4(0) = -(-3)
\n" ); document.write( "=> 3(1) - 0 = 3
\n" ); document.write( "=> 3 = 3\r
\n" ); document.write( "\n" ); document.write( "Since we plugged 2 in place of x in the original equation and got that both sides are equal to each other (3=3), this means that our solution of x=2 is true. If we didn't get both sides to be equal to each other, then our answer would be wrong, and we'd have to go back to the equation and solve it again. \n" ); document.write( "