document.write( "Question 1094162: Find three consecutive odd integers such that the product of the second and third integer minus five times the first integer is 64 \n" ); document.write( "
Algebra.Com's Answer #708781 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
Let your consecutive odd integers be n,n+2, and n+4. Then:
\n" ); document.write( "(n+2)(n+4)-5n=64
\n" ); document.write( "nē+6n+8-5n-64=0
\n" ); document.write( "nē+n-56=0
\n" ); document.write( "(n+8)(n-7)=0
\n" ); document.write( "n=7 or -8
\n" ); document.write( "Choosing the positive value for n, we get n=7,n+2=9, and n+4=11
\n" ); document.write( "☺☺☺☺
\n" ); document.write( " \n" ); document.write( "
\n" );