document.write( "Question 1094128: A hose can fill a swimming pool in 12 hours. Another hose needs 6 more hours to fill the pool than the two hoses combined+How long would it take the second hose to fill the pool? \n" ); document.write( "
Algebra.Com's Answer #708737 by Gentle Phill(18)\"\" \"About 
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Let the 1st hose be A and the 2nd one, B
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\n" ); document.write( "Since A can fill 1 pool in 12 hours
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\n" ); document.write( "A(rate) = 1pool/12hrs
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\n" ); document.write( "Simply put:
\n" ); document.write( "A = 1/12
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\n" ); document.write( "B(rate) = 1pool/xhrs
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\n" ); document.write( "Simply put:
\n" ); document.write( "B = 1/x
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\n" ); document.write( "(A+B) = 1pool/yhrs
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\n" ); document.write( "(A+B) = 1/y
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\n" ); document.write( "(1/12)+(1/x) = 1/y
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\n" ); document.write( "y = 12x/(x+12) ... Eqn 1
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\n" ); document.write( "Just so that you dont get confused;
\n" ); document.write( "~ x = time for which only B fills the pool
\n" ); document.write( "~ y = time for which both A & B fills the pool.
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\n" ); document.write( "But y = x-6hrs
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\n" ); document.write( "Simply put:
\n" ); document.write( "y = x-6
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\n" ); document.write( "Substitute into eqn 1:
\n" ); document.write( "x-6 = 12x/(x+12)
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\n" ); document.write( "(x-6)(x+12) = 12x
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\n" ); document.write( "x2+6x-72 = 12x
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\n" ); document.write( "x2+6x-12x-72 = 0
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\n" ); document.write( "x(x+6)-12(x+6) = 0
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\n" ); document.write( "(x-12)(x+6) = 0
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\n" ); document.write( "x = (12, -6)
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\n" ); document.write( "Since the time can not be a negative value, required x = 12
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\n" ); document.write( "Thus, time for which B fills the pool = 12hrs (same as A)
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\n" ); document.write( "Upon evaluation both will fill in same pool within 6hrs which is 6hrs less than only B or A.
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\n" ); document.write( "Your friend,
\n" ); document.write( "Francis.
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