document.write( "Question 1094047: Two motorcycles are traveling at speeds of 120 kilometers per hour and 90 kilometers per hour respectively. If the faster one travels for 4 hours longer than the slower one and also goes twice as far, how far did the slow one travel? \n" ); document.write( "
Algebra.Com's Answer #708689 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Two motorcycles are traveling at speeds of 120 kilometers per hour and 90 kilometers per hour respectively.
\n" ); document.write( " If the faster one travels for 4 hours longer than the slower one and also goes twice as far, how far did the slow one travel
\n" ); document.write( ":
\n" ); document.write( "let t = the travel time of the slow one
\n" ); document.write( "then
\n" ); document.write( "90t = the distance the slow one traveled
\n" ); document.write( "and
\n" ); document.write( "(t+4) = travel time of the faster cycle
\n" ); document.write( "then
\n" ); document.write( "120(t+4) = the distance of the faster
\n" ); document.write( ":
\n" ); document.write( "A simple equation
\n" ); document.write( "120(t+4) = 2(90t)
\n" ); document.write( "120t + 480 = 180t
\n" ); document.write( "480 = 180t - 120t
\n" ); document.write( "480 = 60t
\n" ); document.write( "t = 480/60
\n" ); document.write( "t = 8 hrs
\n" ); document.write( "therefore
\n" ); document.write( "8 * 90 = 720 km traveled by the slower cycle
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "We can confirm this by find the dist traveled by the faster cycle (4hr longer)
\n" ); document.write( "120 * 12 = 1440 km which is twice as far as the slower \n" ); document.write( "
\n" );