document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1094030>Question 1094030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A local hamburger shop sold a combined total of <BR>\n" );
document.write( "650<BR>\n" );
document.write( " hamburgers and cheeseburgers on Thursday. There were <BR>\n" );
document.write( "50<BR>\n" );
document.write( " fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Thursday?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #708674 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13215)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=708674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>You got a perfectly good formal algebraic solution to your problem....<br><BR>\n" );
document.write( "If you just need to get the answer quickly by any method, try a little logical analysis.<br><BR>\n" );
document.write( "There were a total of 650 burgers sold, with 50 more hamburgers than cheeseburgers.  So \"take away\" those \"extra\" 50 hamburgers; that leaves equal numbers of hamburgers and cheeseburgers, with a total of 600.<BR>\n" );
document.write( "But that means 300 of each.<BR>\n" );
document.write( "Now add back in the \"extra\" hamburgers to find the final answer of 350 hamburgers. </SPAN>\n" );
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