document.write( "Question 1094039: How many gallons of a 80% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 70% antifreeze? \n" ); document.write( "

Algebra.Com's Answer #708670 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "(1) The mixture is 70%; the ingredients are 80% and 30%.
\n" ); document.write( "(2) The 70% is 4 times as close to the 80% as it is to the 30%:
\n" ); document.write( " $\"80-70+=+10\"$ ; $\"70-30=40\"$ ; $\"40=+4%2A10\"$
\n" ); document.write( "(3) Since the mixture percentage is 4 times as close to 80 as it is to 30, the amount of the 80% ingredient must be 4 times the amount of the 30% ingredient.

\n" ); document.write( "That's it. There are 60 gallons of the 30% antifreeze, so the number of gallons of 80% antifreeze must be 4*60 = 240.
\n" ); document.write( " \n" ); document.write( "

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