document.write( "Question 1094064: Walt rode his bike from home to the bicycle repair shop and then walked home. He averaged 18 km/h riding and 6 km/h walking. If his total travel time was one hour, how far is it to the shop from Walt's home? \n" ); document.write( "
Algebra.Com's Answer #708654 by greenestamps(13215)\"\" \"About 
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First a traditional solution using formal algebra....

\n" ); document.write( "Let the distance (in km) be d. Then the number of hours it took him to ride to the repair shop at 18 km/hr is d/18; the number of hours it took him to walk home at 6 km/hr is d/6. Since the total time was 1 hour,

\n" ); document.write( "\"d%2F18+%2B+d%2F6+=+1\"
\n" ); document.write( "\"d+%2B+3d+=+18\"
\n" ); document.write( "\"4d+=+18\"
\n" ); document.write( "\"d+=+4.5\"

\n" ); document.write( "The distance from his home to the repair shop was 4.5 km.

\n" ); document.write( "And now for a solution that is made easier by first doing some logical analysis....

\n" ); document.write( "His walking speed is 1/3 as fast as his riding speed. Since he traveled the same distance riding and walking, he spent 3 times as much time walking as he did riding. Since the total time was 1 hour, he rode for 1/4 hour and walked for 3/4 hour. Then you can find the distance to the repair shop using either the riding part of the trip...
\n" ); document.write( "\"18%2A%281%2F4%29+=+4.5\"
\n" ); document.write( "or the walking part...
\n" ); document.write( "\"6+%2A+%283%2F4%29+=+4.5\"
\n" ); document.write( "
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