document.write( "Question 1094039: How many gallons of a 80% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 70% antifreeze? \n" ); document.write( "

Algebra.Com's Answer #708631 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = gallons of 80% antifreeze needed
\n" ); document.write( "-----------------------
\n" ); document.write( " $\"+%28+.8x+%2B+.3%2A60+%29+%2F+%28+x+%2B+60+%29+=+.7+\"$
\n" ); document.write( " $\"+%28+.8x+%2B+18+%29+%2F+%28+x+%2B+60+%29+=+.7+\"$
\n" ); document.write( " $\"+.8x+%2B+18+=+.7%2A%28+x+%2B+60+%29+\"$
\n" ); document.write( " $\"+.8x+%2B+18+=+.7x+%2B+42+\"$
\n" ); document.write( " $\"+.1x+=+24+\"$
\n" ); document.write( " $\"+x+=+240+\"$
\n" ); document.write( "---------------
\n" ); document.write( "240 gallons of 80% solution are needed
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.8%2A240+%2B+.3%2A60+%29+%2F+%28+240+%2B+60+%29+=+.7+\"$
\n" ); document.write( " $\"+%28+192+%2B+18+%29+%2F+300+=+.7+\"$
\n" ); document.write( " $\"+210+=+.7%2A300+\"$
\n" ); document.write( " $\"+210+=+210+\"$
\n" ); document.write( "OK \n" ); document.write( "

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