document.write( "Question 1093989: find the value of k such that the line through (k,-2) and (5,2) has a slope of 2/3. \n" ); document.write( "
Algebra.Com's Answer #708600 by ankor@dixie-net.com(22740)\"\" \"About 
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find the value of k such that the line through (k,-2) and (5,2) has a slope of 2/3.
\n" ); document.write( "Use the slope formula \"m+=+%28%28y2-y1%29%29%2F%28%28x2-x1%29%29\", where:
\n" ); document.write( "m = 2/3
\n" ); document.write( "x1=k
\n" ); document.write( "y1=-2
\n" ); document.write( "x2=5
\n" ); document.write( "y2=2
\n" ); document.write( ":
\n" ); document.write( "\"%28%282-%28-2%29%29%29%2F%28%285-k%29%29\" = \"2%2F3\"
\n" ); document.write( "\"4%2F%28%285-k%29%29\" = \"2%2F3\"
\n" ); document.write( "cross multiply
\n" ); document.write( "4 * 3 = 2(5-k)
\n" ); document.write( "12 = 10 - 2k
\n" ); document.write( "2k = 10 - 12
\n" ); document.write( "2k = -2
\n" ); document.write( "k = -2/2
\n" ); document.write( "k = -1
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this
\n" ); document.write( " \"4%2F%285-%28-1%29%29\" = \"4%2F6\" = \"2%2F3\"
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