document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1094000>Question 1094000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The cross-sectional area of a certain tree is a linear function of time. If the radius of this circular cross-section was 2 feet in 1915 and 3 feet in 1990, what was it's radius in 2005? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #708593 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=708593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The cross-sectional area of a certain tree is a linear function of time. If the radius of this circular cross-section was 2 feet in 1915 and 3 feet in 1990, what was it's [sic] radius in 2005?<BR>\n" );
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document.write( "(3-2)/(1990 - 1915) = 1/75 ft/yr<BR>\n" );
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document.write( "In 2005:<BR>\n" );
document.write( "3 + (2005 - 1990)*1/75 feet<BR>\n" );
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document.write( "PS  it's = it is\r<BR>\n" );
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