document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1093983>Question 1093983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Begin by graphing the standard quadratic function f(x)=x^2. Then use transformations of this graph to graph the given function. Describe the transformations in words. h(x)=-(x+6)^2+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #708583 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=708583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Same size and shape but h now has lead coefficient  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1 ALIGN=MIDDLE  ALT=\"-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so h is concave downward, and vertex is a maximum point.  Vertex moved from  (0,0) to (-6,2). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );